Calculation of bricks quantities in 1 CFT Wall & in a room
In this short construction article, you will get some quick tricks to measure the numbers of bricks in a masonry wall per cubic foot.
The calculation is made on the basis of the following dimensions :-
- Length (L) of bricks in CFT is taken as 0.75 ft.
- Width (W) of bricks in CFT is taken as 5 inches or 0.41 ft.
- Thickness (T) of Bricks in CFT is taken as 3” or 0.25 ft.
To determine the volume of brick in 1 CFT, multiply Length, Width and Height.
Now, take volume as V.
So, V = L x W x T = 0.75 x 0.41 x 0.25 = 0.076 ft3
Therefore, total numbers of brick in 1 CFT = 1/0.076 = 13.15 bricks
Suppose, the mortar comprises of 10% area.
So, 13.15 x 10/100 = 1.315
So, the total numbers of bricks without mortar = 11.835
Suppose, 5% wastage is occurred in bricks.
So, 11.835 x 5/100 = 0.591
Therefore, total numbers of bricks in 1 CFT = 11.835 + 0.591 = 12.426 or 12.5 (approx)
So, in 1 CFT, the numbers of bricks required = 12.5
Now, calculate the numbers of bricks in a room with area 10 ft x 5 ft.
So, the area of the room = 10 x 5 ft.
As there are two walls inside the room, so it is required to determine the volume for both the walls.
For Wall (1)
- Length (L) of one side wall is taken as 10 ft
- Width (W) of bricks is taken as 0.25 ft
- Height (H) of the wall is taken as 10 ft
- Volume of wall in cft = L x W x H = 10 x 0.25 x 10 = 25 ft3
- For both side= 2 x 25 = 50 ft3
For Wall (2)
- Length (L) of second wall is taken as 5 ft
- Width (W) of bricks is taken as 0.25 ft
- Height (H) of the wall is taken as 10 ft
- Volume of wall in cft = L x W x H = 5 x 0.25 x 10 = 12.5 ft3
- For both sides = 2 x 12.5 = 25 ft3
So, sum of the volume of both walls = 50 ft3 + 25 ft3 = 75 ft3.
From previous calculation, we get 1 CFT = 12.5 bricks
So, numbers of bricks for 75 CFT = 12.5 x 75 = 937.5 bricks
So, the numbers of bricks necessary for building up 10 x 5 ft room = 937.5
